Posted by **Anonymous** on Monday, February 13, 2012 at 10:18am.

Find the surface area of the solid generated by rotating the area between the y-axis, (x^2/y) + y = 1, and -1≤y≤0 is rotated around the y-axis.

- calculus -
**Anonymous**, Monday, February 13, 2012 at 11:10am
you have a circle:

x^2 + (y-1/2)^2 = 1/4

except that as originally written, y cannot be zero.

Now, since the range of y is (0,1], there is no part of the graph below the x-axis. Note that any y < 0 will produce a value such that (y-1/2)^2 > 1/4. That means that x^2 must be negative.

Is this a trick question?

If there's a typo, and you want 0<y<=1, then you are just rotating a semi-circle of radius 1/2, whioch will give you a sphere.

## Answer This Question

## Related Questions

- Calculus - The graph of the curve y2=10 x+10 is a parabola, symmetric with ...
- Calculus - Find the volume generated by rotating about the x axis the area ...
- calculus II SURFACE AREA Integration - Find the exact area of the surface ...
- calculus - The given curve is rotated about the y-axis. Find the area of the ...
- Math - Find the area of the surface generated by revolving the curve y = (x + 3...
- Calculus AP - Let R be the region in the first quadrant bounded by the graph y=3...
- Calc - Set up and evaluate the definite integral for the area of the surface ...
- calculus - Find the surface area generated when y = (x^3/12) + (1/x), from x=1 ...
- asdf - Find a definite integral indicating the area of the surface generated by ...
- Calculus - Find the volume of the solid generated by rotating the region above...

More Related Questions