Thursday

March 5, 2015

March 5, 2015

Posted by **Anonymous** on Monday, February 13, 2012 at 9:33am.

- physics -
**GloryRose**, Saturday, December 15, 2012 at 10:42pmLet X be the length of material of rod A and 30-X be the length of material of rod B. We have

0.065 = (0.045/30)*X + [30-X]*(0.075/30) = 0.0015*X + 0.075 - 0.0025*X or

0.001*X = 0.075 - 0.065 = 0.010 or X = 10 cm. So initial length of rod A was 10 cm and rod B was 20 cm

**Answer this Question**

**Related Questions**

Physics - A Brass rod 50.0 cm long expands 0.0734 cm when heated. Find the ...

Phys - A Brass rod 50.0 cm long expands 0.0734 cm when heated. Find the ...

thermal Energy - Suppose a bar 1 m long expands .5 cm when heated. By how much ...

Physics - A 100.0 cm long brass rod is heated from 20 degrees C to a final temp ...

PHYSICS - A rod 14.0 cm long is uniformly charged and has a total charge of -20....

college physics - A rod 14.0 cm long is uniformly charged and has a total charge...

Physics - A nonuniform 2.0-kg rod is 2.0 m long. The rod is mounted to rotate ...

physics - In a certain experiment, it is necessary to be able to move a small ...

..physics. - At 20.0 C, an alumium ring has an inner diameter of 5.0000 cm and a...

physics - An aluminum rod is 21.5 cm long at 20°C and has a mass of 350 g. If ...