Posted by **sharon** on Monday, February 13, 2012 at 6:34am.

6. A bowl contains 10 red balls, 10 green balls and 10 white balls. a. What is the probability of drawing 2 white balls with replacement? b. What is the probability of drawing 2 white balls without replacement?

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**Reiny**, Monday, February 13, 2012 at 8:09am
when balls are replaced

Prob(2white) = (10/30)(10/30) = 1/9

without replacement

prob(2white) = (10/30)(9/29) = 3/29

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**Anonymous**, Friday, March 14, 2014 at 9:00am
78

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**Motherfu**er**, Tuesday, March 24, 2015 at 8:20pm
where is the fu*n solution

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**Batty**, Monday, May 25, 2015 at 10:15am
Probability of getting 2 white balls (W) with replacement is :

P(W) = ( (10/30) * (10/30) ) = 1/9

Probability of getting 2 white balls (W) without replacement is :

P(W) = ( (10/30) * (9/29) ) = 3/29

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