Wednesday

July 30, 2014

July 30, 2014

Posted by **Heather** on Monday, February 13, 2012 at 1:17am.

- AP Calculus AB -
**Reiny**, Monday, February 13, 2012 at 8:18amI see a thin "triangular" region in quadrant II

form x = -1 to x=0

the "height" is 1 - e^x

area = ∫(1 - e^x) dx from -1 to 0

= [ x - e^x] from -1 to 0

= 0 - 1 - (-1 - e^-1)

= e^-1

or

= 1/e

**Related Questions**

calculus - 1. Find the area of the region bounded by f(x)=x^2 +6x+9 and g(x)=5(x...

calculus - Sketch the region bounded by the graphs of the algebraic functions & ...

calculus - FInd the area of the region bounded by the graphs of y= 3x^2+1 , y=0...

calculus - find the volume of the solid bounded above by the surface z=f(x,y) ...

calculus - Find the area of the region bounded by the graphs f(x)=sqrt(3x)+1, g(...

calculus - Find the area of the region bounded by the graphs of the algebraic ...

Calculus - Find the area of the region bounded by the graphs of the given ...

calculus - find the area the region bounded by the graphs of the given equation ...

calculus - 2. Sketch the region in the first quadrant that is bounded by the ...

calculus - 3). The shaded region is bounded by the y-axis and the graphs of y=1...