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September 16, 2014

September 16, 2014

Posted by **Heather** on Monday, February 13, 2012 at 1:17am.

- AP Calculus AB -
**Reiny**, Monday, February 13, 2012 at 8:18amI see a thin "triangular" region in quadrant II

form x = -1 to x=0

the "height" is 1 - e^x

area = ∫(1 - e^x) dx from -1 to 0

= [ x - e^x] from -1 to 0

= 0 - 1 - (-1 - e^-1)

= e^-1

or

= 1/e

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