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physics

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A 20kg sled is being pulled across a horizontal surface at a constant velocity. The pulling force has a magnitude of 80N and is directed at a angle of 30.0degrees above the horizontal. Determine the coefficient of kinetic friction.

  • physics - ,

    Ws = mg = 20 * 9.8N/kg = 196 N. = Wt. of sled.

    Fs = 196N. @ 0 Deg. = Force of sled.
    Fp = 196*sin(00 = 0 = Force parallel to
    surface.
    Fv = 196*cos(0) = 196 N. = Force perpendicular to surface.

    Fap - Fp - Fk = 0,
    80*cos30 - 0 -u(196-80*sin30) = 0,
    69.3 - u*156 = 0,
    156u = 69.3,
    u = 69.3 / 156 = 0.444.

  • physics - ,

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