Posted by **Natasha** on Monday, February 13, 2012 at 12:14am.

A 20kg sled is being pulled across a horizontal surface at a constant velocity. The pulling force has a magnitude of 80N and is directed at a angle of 30.0degrees above the horizontal. Determine the coefficient of kinetic friction.

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**Henry**, Wednesday, February 15, 2012 at 5:49am
Ws = mg = 20 * 9.8N/kg = 196 N. = Wt. of sled.

Fs = 196N. @ 0 Deg. = Force of sled.

Fp = 196*sin(00 = 0 = Force parallel to

surface.

Fv = 196*cos(0) = 196 N. = Force perpendicular to surface.

Fap - Fp - Fk = 0,

80*cos30 - 0 -u(196-80*sin30) = 0,

69.3 - u*156 = 0,

156u = 69.3,

u = 69.3 / 156 = 0.444.

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