Posted by **JM** on Sunday, February 12, 2012 at 10:31pm.

On what interval is the function f(x)=x^2-6x+8 is increasing?

- Calculus -
**Anonymous**, Monday, February 13, 2012 at 10:40am
come on. even without calculus you know that the vertex is at (3,-1).

With calculus, f' = 2x-6, and f is increasing where f' > 0

## Answer this Question

## Related Questions

- Math - a) Is ∫[-1 to 1]e^x^3 dx positive, negative, or zero? Explain. I think ...
- Algebra - Im having a hard time figuring out this problem: Use the function, y...
- Honors Pre-Calculus - The prompt says "Graph each function. Determine the ...
- calculus - 6) The function f(x)=4x3−18x2−480x−2 is decreasing ...
- Calculus - Consider the following function f(x)=x^2/[x^2-9] f(x) is increasing ...
- Calculus(urgent please help) - Consider the following function f(x)=x^2/[x^2-9] ...
- CALCULUs - For all x in the interval [-11,13] the function f is defined by x^3(x...
- math (calculus) PLZZZ help! - Consider the function below. (Round the answers to...
- Calculus - Answer the following questions for the function f(x) = sin^2(x/3) ...
- Calculus - f(x) = sin^2(x/2) defined on the interval [ -5.683185, 1.270796]. ...

More Related Questions