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March 24, 2017

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When a 58g tennis ball is served, it accelerates from rest to a speed of 45m/s. The impact with the racket gives the ball a constant acceleration over a distance of 44cm. What is the magnitude of the net force acting on the ball?

  • physics - ,

    Vf^2 = Vo^2 + 2a*d.
    a = (Vf^2-Vo^2)/2d,
    a = ((45)^2-0) / 0.88 = 2301 m/s^2.

    Fn = ma = 0.058kg * 2301 = 133.5 N.

    NOTE:

    44 cm = 0.44 m.
    58 g. = 0.058 kg.

  • physics - ,

    133.45

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