Determine the grams of hexane that will react exactly with 22 g of oxygen. Show all working please. Thank you.
To determine the grams of hexane that will react exactly with 22 g of oxygen, we need to balance the chemical equation and use stoichiometry.
The balanced chemical equation for the reaction between hexane (C6H14) and oxygen (O2) is:
2C6H14 + 19O2 → 12CO2 + 14H2O
From the balanced equation, we can see that 2 moles of hexane react with 19 moles of oxygen to produce 12 moles of carbon dioxide and 14 moles of water.
Now let's convert the given mass of oxygen to moles. The molar mass of oxygen (O2) is 32 g/mol.
Number of moles of oxygen = mass of oxygen / molar mass of oxygen
= 22 g / 32 g/mol
= 0.6875 mol (rounded to four decimal places)
Since the ratio between oxygen and hexane in the balanced equation is 19:2, we can use this ratio to find the moles of hexane required.
Number of moles of hexane = (0.6875 mol of oxygen) * (2 mol of hexane) / (19 mol of oxygen)
= 0.0723 mol (rounded to four decimal places)
Now, to find the grams of hexane, we need to multiply the moles of hexane by its molar mass. The molar mass of hexane (C6H14) is 86 g/mol.
Mass of hexane = moles of hexane * molar mass of hexane
= 0.0723 mol * 86 g/mol
= 6.22 g (rounded to two decimal places)
Therefore, approximately 6.22 grams of hexane will react exactly with 22 grams of oxygen.