Posted by Jane on Sunday, February 12, 2012 at 4:32pm.
How do I set this up and how do I solve:
The sum of two numbers is 20 The difference between 3 times the larger number and twice the smaller number is 40. What is the larger number?

Math  Reiny, Sunday, February 12, 2012 at 5:16pm
let the larger be x
let the smaller be 20x
Now just translate ...
three times the larger > 3x
twice the smaller > 2(20x)
that "difference" is 40
3x  2(20x) = 40
3x  40 + 2x = 40
5x = 80
x = 16
the larger is 16
(the smaller is 4)

Math  Jane, Sunday, February 12, 2012 at 5:30pm
Reiny, thank you so much. You broke it down so it was easy to understand.
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