Posted by **Jane** on Sunday, February 12, 2012 at 4:32pm.

How do I set this up and how do I solve:

The sum of two numbers is 20 The difference between 3 times the larger number and twice the smaller number is 40. What is the larger number?

- Math -
**Reiny**, Sunday, February 12, 2012 at 5:16pm
let the larger be x

let the smaller be 20-x

Now just translate ...

three times the larger ---> 3x

twice the smaller ---> 2(20-x)

that "difference" is 40

3x - 2(20-x) = 40

3x - 40 + 2x = 40

5x = 80

x = 16

the larger is 16

(the smaller is 4)

- Math -
**Jane**, Sunday, February 12, 2012 at 5:30pm
Reiny, thank you so much. You broke it down so it was easy to understand.

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