physics
posted by jane .
A car, mass  1950 kg, accelerates at +2.33 m/s (squared). Find the magnitude of the normal force acting on the car. If later, when the car is cruising at 26.5 m/s, the driver applies a force of magnitude 10,000 N to stop the car. What is the distance it takes for the car to come to a stop.

On level ground, the "normal force" is the weight, M*g. The force accelerating the car is M*a. It is not clear what they mean by "normal".
For the stopping distance X,
(stopping force)*X = initial kinetic energy 
normal reaction=m*g
9.81*1950=19129,5newtons
using the equation of motion:s=[(v^2)(u^2)]/2a
4,66s=702,25
thus s=150,7m