Posted by **jane** on Sunday, February 12, 2012 at 8:06am.

A car, mass - 1950 kg, accelerates at +2.33 m/s (squared). Find the magnitude of the normal force acting on the car. If later, when the car is cruising at 26.5 m/s, the driver applies a force of magnitude 10,000 N to stop the car. What is the distance it takes for the car to come to a stop.

- physics -
**drwls**, Sunday, February 12, 2012 at 8:47am
On level ground, the "normal force" is the weight, M*g. The force accelerating the car is M*a. It is not clear what they mean by "normal".

For the stopping distance X,

(stopping force)*X = initial kinetic energy

- physics -
**Marshall**, Thursday, March 15, 2012 at 5:57pm
normal reaction=m*g

9.81*1950=19129,5newtons

using the equation of motion:s=[(v^2)-(u^2)]/2a

4,66s=702,25

thus s=150,7m

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