Friday

April 18, 2014

April 18, 2014

Posted by **Aaron** on Sunday, February 12, 2012 at 1:07am.

to the positive ends of the orthogonal axes. What is the moment of this

force about the origin

So i'm assuming vector r is 4i+5j-7k?

And using the fact that cos^2α + cos^2β + cos^2γ = 1

therefore l=m=n=√1/3

I understand the force vector is equivalent to (26l + 26m + 26n) which equates to: (26/√3 i + 26/√3 j + 26/√3 k)

Thus the moment of force about the origin is (4i+5j+7k) X (26/√3 i + 26/√3 j + 26/√3 k)

This just seems very wrong to me as the cross products would yield very ugly numbers.

I have close to zero confidence in my answer

**Related Questions**

physics - A 26 N force and a 42 N force act concurrently at point P. The larger ...

Engineering/Physics - A force F = 7^i + 6^j - 5^k lb. acts at the origin. Find ...

Algebra II - Forces of 675 lb and 828 ob act on a body. The smaller force acts ...

physics - Three horizontal forces (the only horizontal one) act on a box sitting...

physics - A 3640 lb roller coaster experiences a constant air-resistance force ...

physics - A 3640 lb roller coaster experiences a constant air-resistance force ...

PHYSICS - A potential energy function for a two-dimensional force is of the form...

Physics - A force of 20 N acts toward the west. Another force acts at the same ...

Physics - I came here earlier with this question: "A force of 20 N acts toward ...

physics - A block sits against a vertical wall and a 120 lb force P acts ...