Thursday

December 18, 2014

December 18, 2014

Posted by **Aaron** on Sunday, February 12, 2012 at 1:07am.

to the positive ends of the orthogonal axes. What is the moment of this

force about the origin

So i'm assuming vector r is 4i+5j-7k?

And using the fact that cos^2α + cos^2β + cos^2γ = 1

therefore l=m=n=√1/3

I understand the force vector is equivalent to (26l + 26m + 26n) which equates to: (26/√3 i + 26/√3 j + 26/√3 k)

Thus the moment of force about the origin is (4i+5j+7k) X (26/√3 i + 26/√3 j + 26/√3 k)

This just seems very wrong to me as the cross products would yield very ugly numbers.

I have close to zero confidence in my answer

**Answer this Question**

**Related Questions**

Engineering/Physics - A force F = 7^i + 6^j - 5^k lb. acts at the origin. Find ...

Math - Mark each of the following True or False. ___ a. All vectors in an ...

PHYSICS - Three forces, A,B and C act in the same vertical plane from point O. ...

Physics - A 49-N force is applied perpendicular to the portion BC of the bent ...

Straight Lines - The axes being inclined at an angle of 30°, find the equation ...

Physics - A force of 20 N acts toward the west. Another force acts at the same ...

Physics - I came here earlier with this question: "A force of 20 N acts toward ...

physics - An object is placed on an inclined plane which forms an angle B = 18º ...

Physics - An object is placed on an inclined plane which forms an angle B = 18º ...

Moment/Physics - I understand a moment is a weight being moved by a particular ...