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How much 0.5 M HCl is needed to neutralize 5.5 kg of ammonia dissolved in 6 gal of water?

  • Chemistry -

    NH3 + HCl ==> NH4Cl
    5.5 kg = 5500 g
    Convert to moles.
    moles = grams/molar mass = ?
    1 mole NH3 requires 1 mol HCl; therefore, moles NH3 = moles HCl.
    M HCl = moles HCl/L HCl.
    You know M HCl and moles HCl, solve for L HCl

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