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March 26, 2017

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Calculate the following:
(a) mass of water in the hydrate sample (g):
(b) number of moles of water in the sample:
(c) mass of pure salt in the sample (g):
(d) number of moles of salt in the sample:
(e) molar ratio of water to salt in the sample:


If the mass of the empty crucible (g): 53.200 and the mass of the crucible and hydrate (g): 58.200 and the mass of the crucible and pure salt (g): 56.396

  • chemistry - ,

    I must guess what you did since you didn't post it. I assume
    56.396 = mass xble + salt
    -53.200 = mass empty xble
    --------------
    3.196 g = mass salt

    58.200 = mass xble + hydrate
    -53.200 = mass empty xble
    ---------
    5.000 g = mass hydrate

    5.000 = mass hydrate
    -3.196 = mass salt
    ---------
    1.804 g = mass water added to salt.
    a) 1.804 g
    b) moles = grams/molar mass
    c) see above
    d) It would have helped if you had given a little more information like what you were doing and the name of the salt. moles salt = grams/molar mass
    e) Not enough information provided. You want to find the ratio of moles salt (d) to moles H2O(b)

  • chemistry - ,

    Thank you I been trying to really get the first three I think I figured out the rest through your help thanks.

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