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December 20, 2014

December 20, 2014

Posted by **Phillip** on Saturday, February 11, 2012 at 8:17pm.

- College Physics -
**bobpursley**, Saturday, February 11, 2012 at 9:42pmyou have two acceleation vectors.

One is gravity.

Two is the rocket firing

Both of those is at 90 degrees, so the angle can be found from the tangent when adding those.

Gravity: v^2/r

you are given v (convert to m/s), but r can be found from

v^2/r=g(re/r)^2

or r=g*(rearth/v)^2

gravity acceleration= v^2/g(re/v)^2

figure that out, it is pointed down. Check my math.

Radial acceleration: 21m/s^2

angle= arctan (radial acceleration/gravityacceleration)

check all this , I did it in my head.

- College Physics -
**dark**, Saturday, February 9, 2013 at 6:58pmbobpursley's answer is wrong. The question isn't a satellite revolving earth anyways.

- College Physics -
**dark**, Saturday, February 9, 2013 at 7:27pmTotal Acceleration will consist of Centripetal (which is in the same direction as the r vector) and Tangential (which at any given moment will be your retarding one. With that we can set up a triangle that gives us the angle needed.

Since we don't know radius we can use V=r2Pi/T and solve for Centripetal.

We get V2Pi/T= Ac. From Ac=V^2/r and using our solve for r from above.

Our answer will be |arctan( Aretarding/Ac)|:

|arctan(21/(V2Pi/T))=67.96deg

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