Thursday
March 30, 2017

Post a New Question

Posted by on .

The highest barrier that a projectile can clear is 12.7 m, when the projectile is launched at an angle of 17.5° above the horizontal. What is the projectile's launch speed?

  • physics - ,

    The vertical initial speed is Vsin17.5

    the vertical speed at max height is zero.

    Vf^2=(Vsin17.5)^2-2*9.8*12.7
    solve for V, knowing Vf is zero.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question