You have a fair die. The die has a 2 on two sides, a 4 on two sides and a 6 on two sides. Note: the only possible outcomes for each roll are 2, 4 or 6. (a) Draw a tree diagram that shows the possible outcomes of rolling the die twice (my answer Roll 1: 2, 4, 6 Roll 2: 2,4,6 and 2,4,6 and 2,4,6 Sum 4,6,8 and 6,8,10 and 8,10, 12) (b) What is the probability of the two die summing to 10? HELP. Thank you

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To draw a tree diagram for this problem, we can start by listing all the possible outcomes for the first roll: 2, 4, and 6. Then, for each of these outcomes, we list the possible outcomes for the second roll: 2, 4, and 6 again.

Here is the tree diagram:

1st Roll
/ / \
2 4 6
/ | \ / | \ / | \
2 4 6 2 4 6 2 4 6

In the tree diagram, each path from the first roll to the second roll represents a possible outcome. For example, the path from 2 to 2 represents the outcome of rolling a 2 on the first roll and a 2 on the second roll.

Now, let's move on to calculating the probability of rolling a sum of 10 on the two dice. To do this, we need to count the number of outcomes that result in a sum of 10 and divide it by the total number of possible outcomes.

From the tree diagram, we can see that there is only one way to get a sum of 10, which is by rolling a 4 on the first roll and a 6 on the second roll.

Therefore, the probability of rolling a sum of 10 is 1 out of 9 (since there are a total of 9 possible outcomes), which can be simplified to 1/9.

So, the probability of rolling a sum of 10 on the two dice is 1/9.