How do you find the ratio of moles of oxygen to moles of tin?
What would be the Empirical formula of tin oxide from the result of ratio?
From my calculations I got the moles as:
Moles of oxygen = 1.761 x 10^-2
Moles of Tin = 8.944 x 10^-3
Thanks!
Your question is a little cryptic. I assume you have grams of something and you've converted those to moles. You want the empirical formula from that. If that is the case, you want the ratio of mole of Sn to moles O with the smalles number being 1.00. The easy way top do that is top divide the smallest number by itself; i.e., 8.944E-3/8.944E-3 = 1.00. That assures you of getting one for that one. Then divide the other number by the same small number. That will be 1.761E-2/8.944E-3 = 1.9689 which rounds to 2.0 so it's SnO2.
Ah, the ratio of moles of oxygen to moles of tin, huh? Well, you know what they say, finding ratios is like finding a needle in a moles-stack.
Anyway, to find the ratio, we need to divide the moles of oxygen by the moles of tin. So, if we divide 1.761 x 10^-2 moles of oxygen by 8.944 x 10^-3 moles of tin, we get approximately 1.968 moles of oxygen per mole of tin.
Now, onto the empirical formula of tin oxide! With this ratio, we can say that the empirical formula of tin oxide is SnO2. So, tin oxide is made up of one tin atom and two oxygen atoms. Gotta love those chemical formulas, always coming in pairs!
To find the ratio of moles of oxygen to moles of tin, we divide the number of moles of oxygen by the number of moles of tin:
Moles of oxygen / Moles of tin = (1.761 x 10^-2) / (8.944 x 10^-3) = 1.964
Therefore, the ratio of moles of oxygen to moles of tin is approximately 1.964.
To determine the empirical formula of tin oxide from this ratio, we need to simplify the ratio to its simplest whole number ratio. In this case, we can multiply both the number of moles of oxygen and tin by 3 to obtain whole number results:
Moles of oxygen: 1.761 x 10^-2 x 3 = 5.283 x 10^-2
Moles of tin: 8.944 x 10^-3 x 3 = 2.683 x 10^-2
The simplified ratio would be:
Moles of oxygen / Moles of tin = (5.283 x 10^-2) / (2.683 x 10^-2) ≈ 1.967
Therefore, the simplified ratio of moles of oxygen to moles of tin is approximately 1.967.
From this ratio, the empirical formula of tin oxide would be SnO2.
To find the ratio of moles of oxygen to moles of tin, you simply divide the number of moles of oxygen by the number of moles of tin.
Ratio of moles of oxygen to moles of tin = Moles of oxygen / Moles of tin
In this case, the moles of oxygen is given as 1.761 x 10^-2 and the moles of tin is given as 8.944 x 10^-3. So, the ratio would be:
Ratio of moles of oxygen to moles of tin = (1.761 x 10^-2) / (8.944 x 10^-3)
To simplify this ratio, you can divide both the numerator and the denominator by the smallerscientific factor, which in this case is 8.944 x 10^-3.
First, let's convert both numbers to scientific notation for easier calculation:
Moles of oxygen = 1.761 x 10^-2
Moles of tin = 8.944 x 10^-3
Now, divide both numbers by 8.944 x 10^-3:
(1.761 x 10^-2) / (8.944 x 10^-3) = 1.969
So, the ratio of moles of oxygen to moles of tin is approximately 1.969.
Now, let's move on to the empirical formula of tin oxide. The empirical formula represents the simplest ratio of atoms in a compound. To determine the empirical formula, you need the molar ratios between the elements.
For tin oxide, the ratio of oxygen to tin is 1.969 (approximately). Therefore, the empirical formula of tin oxide would be SnO2.