Posted by brett on Saturday, February 11, 2012 at 3:51pm.
Before hopping on,
Momentum = 36.4* 2.2 = 80.08 kg m/s
After hopping on,
Momentum = (36.4 + 2.3 + 22.7)*1.3 = 79.82 m/s
Since there are only two significant figures in your numbers, the 0.3% computed decrease in momentum is not significant. No momentum should have been lost at all. There is a law that says there should be no total momentum decrease if there are no "outside forces" , but friction while getting on may have reduced it slightly.
Related Questions
physics - A 41.2 kg student runs down the sidewalk and jumps with a horizontal ...
Physics - A 42.5 kg student runs down the sidewalk and jumps with a horizontal ...
physics - A 200kg turtle running at a speed of .4m/s jumps onto a stationary ...
physics - a 43.7 kg student runs down the sidewalk and jumps with a horizontal ...
physics - a 43.7 kg student runs down the sidewalk and jumps with a horizontal ...
physics - a 43.7 kg student runs down the sidewalk and jumps with a horizontal ...
physics - A woman with a mass of 41 kg runs at a speed of 7 m/s and jumps onto a...
physics - A woman with a mass of 56 kg runs at a speed of 8 m/s and jumps onto a...
PHYSICS HELP !!!!! - A 55 kg person runs with a horizontal velocity of 8.0 m/s ...
physics - A 65 kg person runs with a horizontal velocity of 3.5 m/s and jumps ...
For Further Reading