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August 1, 2014

August 1, 2014

Posted by **Mishaka** on Saturday, February 11, 2012 at 3:27pm.

3x(x^2 + 7)^3

- Calculus (Antiderivatives) -
**Steve**, Saturday, February 11, 2012 at 6:02pmhard way: expand the product:

3x^7 + 63x^5 + 441x^3 + 1029x

integral is

3/8 x^8 + 21/2 x^6 + 441/4 x^4 + 1029/2 x^2

easy way: let u = x^2+7

du = 2x dx

Integral of 3/2 u^3 du

is

3/8 u^4 = 3/8 (x^2+7)^4

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