February 23, 2017

Homework Help: Calculus

Posted by Matthew on Saturday, February 11, 2012 at 3:27pm.

Is this the right explanation for this question

1. Examine the continuity of the function


-x, if x<0
0, if x=0
x, if x>0

Answer: Since h(x)=
-x, if x<0
0, if x=0
x, if x>0 is h=|x|,

we can conclude that the function is

1. continuous everywhere

2. discontinuous at x=0 because limit from the left (-1) and limit from the right (+1) does not equal the same value, therefore it doesn't exist.

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