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September 16, 2014

September 16, 2014

Posted by **Matthew** on Saturday, February 11, 2012 at 1:16am.

Examine the continuity of the function

h(x)=

-x, if x<0

0, if x=0

x, if x>0

- Calculus -
**Matthew**, Saturday, February 11, 2012 at 2:39amWhat would be discontinous at x=?

explain please

- Calculus -
**Steve**, Saturday, February 11, 2012 at 5:31amThis is just h(x) = |x|

h is continuous at x=0, but

h' is discontinuous at x=0, since

h'(x) = -1 for x < 0

h'(x) = 1 for x > 0

- Calculus -
**Matthew**, Saturday, February 11, 2012 at 1:36pmIs there suppose to be calculations involved? :|

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