Posted by Matthew on Saturday, February 11, 2012 at 1:16am.
What would be discontinous at x=?
explain please
This is just h(x) = |x|
h is continuous at x=0, but
h' is discontinuous at x=0, since
h'(x) = -1 for x < 0
h'(x) = 1 for x > 0
Is there suppose to be calculations involved? :|
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