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Can someone help me with this question. With steps.

Examine the continuity of the function


-x, if x<0
0, if x=0
x, if x>0

  • Calculus - ,

    What would be discontinous at x=?

    explain please

  • Calculus - ,

    This is just h(x) = |x|
    h is continuous at x=0, but

    h' is discontinuous at x=0, since
    h'(x) = -1 for x < 0
    h'(x) = 1 for x > 0

  • Calculus - ,

    Is there suppose to be calculations involved? :|

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