Posted by Matthew on Saturday, February 11, 2012 at 1:16am.
Can someone help me with this question. With steps.
Examine the continuity of the function
h(x)=
x, if x<0
0, if x=0
x, if x>0

Calculus  Matthew, Saturday, February 11, 2012 at 2:39am
What would be discontinous at x=?
explain please

Calculus  Steve, Saturday, February 11, 2012 at 5:31am
This is just h(x) = x
h is continuous at x=0, but
h' is discontinuous at x=0, since
h'(x) = 1 for x < 0
h'(x) = 1 for x > 0

Calculus  Matthew, Saturday, February 11, 2012 at 1:36pm
Is there suppose to be calculations involved? :
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