Posted by Yvonne on Saturday, February 11, 2012 at 12:02am.
That can be solved by separation of variables.
y^2 dy = (x+1) dx
y^3/3 = x^2/2 + x + C
If y(0) = 3, then C = 3
y^3/3 = x^2/2 + x + 3
3^3/3 = C
C = 9
Steve is correct.
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