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February 1, 2015

February 1, 2015

Posted by **Jose** on Friday, February 10, 2012 at 10:08pm.

- Math -
**Steve**, Saturday, February 11, 2012 at 5:15amv = Int(pi*(R^2-r^2) dx) [0,1]

where

R = 5cosh(x)

r = 5sinh(x)

v = 5pi*Int(cosh(x) - sinh(x) dx) [0,1]

= 5pi*(sinh(x)-cosh(x))[0,1]

=5pi*[(sinh(1)-cosh(1))-(sinh(0)-cosh(0))

= 5pi*(-1/e + 1)

= 5pi(e-1)/e

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