Math
posted by Jose on .
Find the volume of the solid generated by revolving the region bounded by y= 5 cosh (x) and y= 5 sinh (x) between x = 0 and x = 1 about the xaxis

v = Int(pi*(R^2r^2) dx) [0,1]
where
R = 5cosh(x)
r = 5sinh(x)
v = 5pi*Int(cosh(x)  sinh(x) dx) [0,1]
= 5pi*(sinh(x)cosh(x))[0,1]
=5pi*[(sinh(1)cosh(1))(sinh(0)cosh(0))
= 5pi*(1/e + 1)
= 5pi(e1)/e