Posted by Hank on Friday, February 10, 2012 at 9:26pm.
y=3+2ln|x|
y = 3x + 2(x+1)^-1
dy/dx = 3 -2(x+1)^-2 or
= 3 - 2/(x+1)^2
y = (3x+2)/(x+1)
y' = [(3)(x+1) - (3x+2)(1)]/(x+1)^2
= (3x + 3 - 3x - 2)/(x+1)^2
= 1/(x+1)^2
See what a difference proper punctuation makes? Three reasonable interpretations of your problem, all giving different solutions.
USE PARENTHESES FOR CLARITY!
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