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July 29, 2014

July 29, 2014

Posted by **Hank** on Friday, February 10, 2012 at 9:26pm.

y = 3x+2/x+1

- Calculus -
**Jana**, Friday, February 10, 2012 at 9:48pmy=3+2ln|x|

- Calculus -
**Reiny**, Friday, February 10, 2012 at 11:57pmy = 3x + 2(x+1)^-1

dy/dx = 3 -2(x+1)^-2 or

= 3 - 2/(x+1)^2

- Calculus -
**Steve**, Saturday, February 11, 2012 at 5:08amy = (3x+2)/(x+1)

y' = [(3)(x+1) - (3x+2)(1)]/(x+1)^2

= (3x + 3 - 3x - 2)/(x+1)^2

= 1/(x+1)^2

See what a difference proper punctuation makes? Three reasonable interpretations of your problem, all giving different solutions.

USE PARENTHESES FOR CLARITY!

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