Posted by **Marc** on Friday, February 10, 2012 at 9:05pm.

Wheel A of radius ra = 13.9 cm is coupled by belt B to wheel C of radius rc = 34.3 cm. Wheel A increases its angular speed from rest at time t = 0 s at a uniform rate of 5.7 rad/s2. At what time will wheel C reach a rotational speed of 168.2 rev/min, assuming the belt does not slip?

- Physics -
**drwls**, Friday, February 10, 2012 at 9:26pm
The product of rotational speed and radius is the same for each wheel. So is the product of angular acceleration and radius. Use those facts to deduce the time required.

- Physics? -
**Marc**, Friday, February 10, 2012 at 9:43pm
ok..so for c: v = w*r = 168.2*0.343m =57.6926

and therefore for a: w = v/r = 57.6926/0.139m = 415.055

is that correct?

and for the acceleration:

for a: a= 5.7*0.139 = 0.7923

and for c: 0.7923/0.343 = 2.3099

but how do I get time ??

- Physics -
**drwls**, Saturday, February 11, 2012 at 2:39am
I thought I told you that before.

To get the time, divide the angular velocity change by the angular acceleration

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