Posted by Marc on Friday, February 10, 2012 at 9:05pm.
Wheel A of radius ra = 13.9 cm is coupled by belt B to wheel C of radius rc = 34.3 cm. Wheel A increases its angular speed from rest at time t = 0 s at a uniform rate of 5.7 rad/s2. At what time will wheel C reach a rotational speed of 168.2 rev/min, assuming the belt does not slip?

Physics  drwls, Friday, February 10, 2012 at 9:26pm
The product of rotational speed and radius is the same for each wheel. So is the product of angular acceleration and radius. Use those facts to deduce the time required.

Physics?  Marc, Friday, February 10, 2012 at 9:43pm
ok..so for c: v = w*r = 168.2*0.343m =57.6926
and therefore for a: w = v/r = 57.6926/0.139m = 415.055
is that correct?
and for the acceleration:
for a: a= 5.7*0.139 = 0.7923
and for c: 0.7923/0.343 = 2.3099
but how do I get time ??

Physics  drwls, Saturday, February 11, 2012 at 2:39am
I thought I told you that before.
To get the time, divide the angular velocity change by the angular acceleration
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