Show work to change the linear equation below to slope-intercept form and then, list the slope and y intercept coordinate for the: (leave answers as an integer or a fraction in improper form).
20+3x-8y=0
slope-intercept form:
y = mx+b
20+3x-8y=0
8y=3x+20
y = 3/8 x + 5/2
now just read off the slope and intercept.
To change the linear equation 20+3x-8y=0 to slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept, we need to isolate the term with y on one side of the equation.
1. Start by subtracting 20 from both sides of the equation:
20 + 3x - 8y - 20 = 0 - 20
3x - 8y = -20
2. Next, rearrange the equation by moving the 3x term to the other side of the equation:
3x - 8y = -20 ⇒ 3x = 8y - 20
3. Now, divide both sides of the equation by 3 to solve for x:
(3x) / 3 = (8y - 20) / 3
x = (8/3)y - 20/3
The equation is now in slope-intercept form (y = mx + b) where the slope (m) is 8/3 and the y-intercept (b) is -20/3.