TRIG
posted by Anonymous .
In a right triangle ABC, C = 90°, b = 380.1 inches and c = 589.1 inches. Solve for all the missing parts using the given information. (Round each answer to one decimal place for side and to two decimal places for angles.)
A = °
B = °
a = inches
IM lOST!

You have a rightangled triangle , so basic trig is needed here
Make a sketch
looks like cosA = adjacent/hypotenuse = 380.1/589.1 = .64522....
Angle A = 49.82°
B = 90°  A , you do that one
sinA = a/589.1
a = 589.1sin 49.82 = 450.0