In a rocket, fuel burns at the rate of 1kg/s. This fuel is Ejected from the rocket with a velocity of 60km/s. What force will be exerted on the rocket?
F = m * a
1 N = 1 kg * 1 m / s^2
M = 1 kg / sec
V = 60 km /sec
F = 1 kg / sec * 60 km / sec
F = 60 * 1000 * kg / sec^2
F = 60000 N
Ans: 60,000 N
To find the force exerted on the rocket, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration. In this case, the acceleration is the change in velocity over time.
Given:
Rate of fuel burn = 1 kg/s
Velocity of fuel ejected = 60 km/s
First, let's convert the velocity from km/s to m/s, as the unit of force is in Newtons (N), which uses meters per second (m/s).
1 km = 1000 m
60 km/s = 60,000 m/s
Now, let's consider the change in velocity for each kilogram of fuel burned. Since the fuel is ejected at a velocity of 60,000 m/s, and the rocket is initially at rest, the change in velocity is 60,000 m/s.
Next, we need to determine the mass of the fuel burned per second. Given that the rate of fuel burn is 1 kg/s, this means that 1 kilogram of fuel is burned per second.
To find the force, we multiply the mass of the fuel burned (1 kg/s) by the change in velocity (60,000 m/s):
Force = mass x change in velocity
= 1 kg/s x 60,000 m/s
= 60,000 N
Therefore, the force exerted on the rocket is 60,000 Newtons.