math
posted by deana on .
using this information: if an object is thrown straight up into the air from the height H feet per second then at time tseconds the height of the object is
16.1t^2 +Vt+ H feet.
This formula uses only gravitational force, ignoring air friction. It is valid only until the object hits the ground or some other object.
Find a function b such that b(v) is the length of time in seconds that a ball takes to reach its maximum height when thrown straight up with initial velocity V feet per second

b = (VfVo)/g.
Vf = 0 at max ht.
b = (0Vo)/32.