Posted by SMK on Friday, February 10, 2012 at 8:51am.
A 210W heater is placed in 2KG of water. What temperature rise is produced if the heater is switched on for 200 seconds?

Physics  drwls, Friday, February 10, 2012 at 9:05am
delta T = (heat energy added)/(M*C)
= (210 J/s*200s)/(M*C)
= 4.2*10^4 J/(M*C)
= 10,050 calories/(2 kg*1000 cal/kgC)
= 5.0 degrees
I converted to calories so I could use the easily remembered specific heat of water (C) in calorie/kg*C .

Physics  SMK, Friday, February 10, 2012 at 9:31am
So without converting to calories the answer would be 21 degree C, right?
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