posted by SMK on .
A 210W heater is placed in 2KG of water. What temperature rise is produced if the heater is switched on for 200 seconds?
delta T = (heat energy added)/(M*C)
= (210 J/s*200s)/(M*C)
= 4.2*10^4 J/(M*C)
= 10,050 calories/(2 kg*1000 cal/kgC)
= 5.0 degrees
I converted to calories so I could use the easily remembered specific heat of water (C) in calorie/kg*C .
So without converting to calories the answer would be 21 degree C, right?