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A 210W heater is placed in 2KG of water. What temperature rise is produced if the heater is switched on for 200 seconds?

  • Physics -

    delta T = (heat energy added)/(M*C)
    = (210 J/s*200s)/(M*C)
    = 4.2*10^4 J/(M*C)
    = 10,050 calories/(2 kg*1000 cal/kgC)
    = 5.0 degrees

    I converted to calories so I could use the easily remembered specific heat of water (C) in calorie/kg*C .

  • Physics -

    So without converting to calories the answer would be 21 degree C, right?

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