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July 28, 2014

July 28, 2014

Posted by **joe** on Friday, February 10, 2012 at 6:18am.

- trigonometry -
**Reiny**, Friday, February 10, 2012 at 8:17amConstruct the trapezoid ABCD ,where AB || CD

AB = 12 and CD = 22

angle C=65 and angle D = 40

Draw AE || BC where E is on CD

So now ABCE is a parallelogram, and CE = 12

which makes ED = 10

Now look at triangle AED, by corresponding angles

angle AED = 65°, angle D = 40 leaving angle DAE = 75°

by sine law:

AD/sin65 = 10/sin75

AD = 10sin65/sin75 = 9.38

by sine law:

AE/sin40 = 10/sin75

AE = 6.65

but BC = AE, (||gram|

So the side adjacent to the 65° angle is 6.65, the side adjacent to the 40° angle is 9.38

check my arithmetic, I am only on my first coffee.

- trigonometry -
**joanne**, Thursday, March 15, 2012 at 12:00amwow this really helps!! :D I have the same problem too haha thanks!!!

- trigonometry -
**Paul**, Thursday, July 4, 2013 at 7:50amHey thanks! I have the same problem. never thought it would be this easy.

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