posted by Carey on .
A researcher studying the nutritional value of a new candy places a 4.90 gram sample of the candy inside a bomb calorimeter and combusts it in excess oxygen. The observed temperature increase is 2.75 Celsius. If the heat capacity of the calorimeter is 29.50 kJ K^-1, how many nutritional calories are there per gram of the candy? Answer in cal/g
29,500 J/K x 2.75 K = about 81,000 J(approximate) from the combustion.
81,000 J/4.90 = about 16,000 J/g.
16,000 J/g x (1 cal/4.184 J) = about 4,000 cal.
4,000 cal = 4 kcal = about 4 nutritional calories.
that's amazing... thank you so much Dr Bob!
Thank you so much!!! That helped me too!
Wouldn't you have to convert the temperature to K in order to cancel out the units and obtain a value in joules. For the very first step of the solution