A 75.0 kg diver steps off a diving board and drops straight down into the water. The water provides an upward average net force 1060 N. If the diver comes to rest 4.9 m below the water's surface, what is the total distance between the diving board and the diver's stopping point underwater?

Work done opposing the upward buoyant force equals P.E loss from the diving board to the stopping point

1060N*4.9 m = M g X
M g = 735 N
X is the distance you want.

X = (1060/735)4.9 = 7.1 meters

The height of the diver is being neglected here.

To find the total distance between the diving board and the diver's stopping point underwater, we need to consider the distance traveled both before and after the diver comes to rest.

First, let's calculate the distance traveled until the diver comes to rest. We can use the work-energy principle:

Work done by the water's upward force = change in kinetic energy

The work done by the water's upward force is given by:

Work = Force x Distance

= 1060 N x 4.9 m

= 5194 N·m = 5194 J

The change in kinetic energy is given by:

Change in KE = (1/2)mv^2

Since the diver comes to rest, the final velocity is 0, so:

Change in KE = (1/2)mv^2 = (1/2)(75.0 kg)(0)^2 = 0 J

Since the work done by the water's upward force is equal to the change in kinetic energy, we have:

5194 J = 0 J + 0 J

5194 J = 0 J

Now, let's calculate the distance traveled until the diver comes to rest:

5194 J = mgd

5194 J = (75.0 kg)(9.8 m/s^2)(d)

Solving for d:

d = 5194 J / (75.0 kg x 9.8 m/s^2)

d ≈ 7.07 m

Therefore, the distance traveled until the diver comes to rest is approximately 7.07 meters.

To find the total distance, we sum up the distance traveled before and after the diver comes to rest:

Total distance = Distance traveled until the diver comes to rest + Distance traveled after the diver comes to rest

= 7.07 m + 4.9 m

= 11.97 m

Therefore, the total distance between the diving board and the diver's stopping point underwater is approximately 11.97 meters.

To find the total distance between the diving board and the diver's stopping point underwater, we need to calculate the distance the diver travels in the air and then add it to the distance the diver travels underwater.

First, let's calculate the distance the diver travels in the air. We can use the kinematic equation:

s = ut + (1/2)at^2

where s is the distance, u is the initial velocity, t is the time, and a is the acceleration.

In this case, the diver starts from rest, so the initial velocity (u) is 0. The acceleration (a) can be calculated using Newton's second law:

F = ma

where F is the net force and m is the mass of the diver. Rearranging the equation, we have:

a = F / m

Plugging in the values, we get:

a = 1060 N / 75 kg ≈ 14.133 m/s²

Now, we can find the time it takes for the diver to reach the water's surface. Using the equation:

v = u + at

where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time, we can solve for t:

0 = 0 + 14.133 m/s² * t

Simplifying the equation, we get:

t = 0 / 14.133 m/s² = 0 s

Since the initial velocity is 0, the time taken to reach the water's surface is 0 seconds.

Next, let's calculate the distance the diver travels underwater. Using the equation:

s = ut + (1/2)at^2

where s is the distance, u is the initial velocity, t is the time, and a is the acceleration, we can solve for s:

s = 0 m/s * t + (1/2) * 9.8 m/s² * t²

Simplifying the equation, we have:

s = (1/2) * 9.8 m/s² * t²

Substituting the time t = 0 s, the distance traveled underwater (s) is also 0.

Finally, we can calculate the total distance by adding the distance traveled in the air (0 m) to the distance traveled underwater (0 m):

Total distance = 0 m + 0 m = 0 m

Therefore, the total distance between the diving board and the diver's stopping point underwater is 0 meters.