posted by Jeremy on .
The reaction 2NO2--->2NO+O2 has the rate constant k= 0.68 m-1s-1.
If the initial concentration of NO2 is 9.30×10−2 M, how long it would take for the concentration to decrease to 2.00×10−2 M ?
please answer and show the steps
ln (A)t - ln(A)o = -kt
ln2.00x10-2 - ln(9.30x10-2) = -.68 t
t = 2.26s
Hope this is right!