Chemistry
posted by Jeremy on .
The reaction 2NO2>2NO+O2 has the rate constant k= 0.68 m1s1.
If the initial concentration of NO2 is 9.30×10−2 M, how long it would take for the concentration to decrease to 2.00×10−2 M ?
please answer and show the steps

ln (A)t  ln(A)o = kt
ln2.00x102  ln(9.30x102) = .68 t
t = 2.26s
Hope this is right!