(x+1/8)(x-9/8)
( x + 1 / 8 )( x - 9 / 8 )=
x * x + x / 8 - 9 x / 8 - 1 * 9 / ( 8 * 8 ) 0
x ^ 2 - 8 x / 8 - 9 / 64 =
x ^ 2 - x - 9 / 64
??
(x + 1/8) = (8x+1)/8
(x - 9/8) = (8x-9)/8
(x + 1/8)/(x - 9/8) = (8x+1)/(8x-9)
To multiply the expressions (x+1/8)(x-9/8), you can use the distributive property.
Step 1: Multiply the first terms of each binomial together:
(x)*(x) = x^2
Step 2: Multiply the outer terms of each binomial together:
(x)*(-9/8) = -9x/8
Step 3: Multiply the inner terms of each binomial together:
(1/8)*(x) = x/8
Step 4: Multiply the last terms of each binomial together:
(1/8)*(-9/8) = -9/64
Step 5: Add up all the terms:
x^2 - 9x/8 + x/8 - 9/64
Step 6: Simplify the expression:
Combining like terms, we have:
x^2 - 8x/8 - 9/64
Simplifying further, we get:
x^2 - x - 9/64
So the product of (x+1/8)(x-9/8) is x^2 - x - 9/64.