Posted by Sam on Thursday, February 9, 2012 at 9:45pm.
I'm a little confused as to the question. If you want percent water (not counting the solutions) it is (4/10)*100 = ?
If you want to count the water in the aq NaOH too that is almost 2 mL (0.01M NaOH is only 0.4 g NaOH in a liter which will be 0.4 mg in 1 mL or 0.8 mg in 2 mL which is about 2000 mg H2O - 0.8 mg NaOH = 1999.2 mg H2O and for all practical purposes that is 2 mL. We could do it more accurately if we knew the density of the 0.01 M solution.)
That will make it 4mL + 2 mL = 6 mL out of a total of 10 mL so percent H2O is (6/10)*100 = ?
There is no acetone in the water so you can ignore those calculations.
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