Posted by **archi** on Thursday, February 9, 2012 at 9:15pm.

Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis.

y=2+1/x^4,y=2,x=4,x=9;

about the x-axis.

- calculus - please help! -
**Steve**, Friday, February 10, 2012 at 10:07am
Int(2 + 1/x^4 - 2 dx)[4,9]

= -1/3 x^-3 [4,9]

= -1/3(1/729 - 1/64)

= 665/139968

= 0.00475

- calculus - oops -
**Steve**, Friday, February 10, 2012 at 10:13am
Sorry - we wanted a solid

v = Int(pi (R^2-r^2) dx)

where R = y = 2+x^-4

and r = 2

pi*Int(2+x^-4)^2 - 4 dx [4,9]

pi*Int(4+4x^-4 + x^-8 - 4 dx)[4,9]

pi*Int(4x^-4 + x^-8 dx) [4,9]

-pi*(28/x^3 + 1/7x^7)

= 0.0597

- calculus - please help! -
**archi**, Friday, February 10, 2012 at 2:34pm
thank you soo much! :D

- calculus - please help! -
**Steve**, Friday, February 10, 2012 at 5:51pm
Hmm. I didn't see where you specified an axis. I rotated around the x-axis.

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