Calculate the molarity of 2.05 L of a solution containing 1.51 g of dissolved KBr
Find the g/mol for KBr
1.51g x 1mol/g/mol of KBr
you should've gtt the answer for the mol
the formula for molarity is M = mol/L
plug the mol answer that you just found and divided by 2.05L
Then you should;ve got the answer for molarity
To calculate the molarity of a solution, we need to know the amount of solute (in moles) and the volume of the solution (in liters).
First, we need to convert the mass of KBr to moles. To do this, we will use the molar mass of KBr, which is the sum of the atomic masses of potassium (K) and bromine (Br).
Atomic mass of K = 39.10 g/mol
Atomic mass of Br = 79.90 g/mol
Molar mass of KBr = (39.10 g/mol) + (79.90 g/mol) = 119.00 g/mol
Now, let's calculate the number of moles of KBr:
Number of moles = mass of KBr / molar mass of KBr
= 1.51 g / 119.00 g/mol
Next, we need to convert the volume of the solution from liters to moles. In this case, the volume is already given in liters, so no conversion is needed.
Finally, we can calculate the molarity of the solution:
Molarity (M) = moles of KBr / volume of solution (in liters)
= (1.51 g / 119.00 g/mol) / 2.05 L
Let's perform the calculation:
Molarity (M) = (0.0127 mol) / 2.05 L
= 0.00620 M
Therefore, the molarity of the solution is 0.00620 M.