Posted by **Helen** on Thursday, February 9, 2012 at 4:57pm.

A bucket contains blue balls and yellow balls. the probability of removing two blue balls without replacement is 2/5 and he probability of removing three blue balls without replacement is 1/5. Why must there be two more blue balls then yellow balls? How many red balls were in the bucket. show that b=y+2

- Math -
**Steve**, Thursday, February 9, 2012 at 8:56pm
b/(b+y) * (b-1)/(b+y-1) = 2/5

b/(b+y) * (b-1)/(b+y-1) * (b-2)(b+y-2) = 1/5 = 1/2 * 2/5

so,

(b-2)/(b+y-2) = 1/2

2(b-2) = b+y-2

2b-4 = b+y-2

b = y+2

no idea about any red balls, but

(y+2)/(2y+2) * (y+1)/(2y+1) = 2/5

(y+2)/2(2y+1) = 2/5

5y+10 = 8y+4

3y = 6

y=2

so, b=4

4/6*3/5 = 2/5

2/5*2/4 = 1/5

## Answer This Question

## Related Questions

- math - A box contains 8 blue balls and 2 red balls. Three balls are selected ...
- statistics - A jar contains 7 red balls, 5 green balls, 4 blue balls, and 3 ...
- Probability again - A box contains 6 red balls, 4 blue balls, and 2 green balls...
- Math - Assume that you are drawing two balls without replacement from an urn ...
- statistics - A jar contains 2 red balls, 2 blue balls, 2 green balls and 1 ...
- Statistics - An urn contains three yellow,four green and five blue balls. Two ...
- stats - A box contains 10 red balls and 20 blue balls. Three balls are selected ...
- math probability - Four balls are selected at random without replacement from ...
- probability - Four balls are selected at random without replacement from an urn...
- math - Four balls are selected at random without replacement from an urn ...

More Related Questions