Posted by Helen on Thursday, February 9, 2012 at 4:57pm.
b/(b+y) * (b-1)/(b+y-1) = 2/5
b/(b+y) * (b-1)/(b+y-1) * (b-2)(b+y-2) = 1/5 = 1/2 * 2/5
so,
(b-2)/(b+y-2) = 1/2
2(b-2) = b+y-2
2b-4 = b+y-2
b = y+2
no idea about any red balls, but
(y+2)/(2y+2) * (y+1)/(2y+1) = 2/5
(y+2)/2(2y+1) = 2/5
5y+10 = 8y+4
3y = 6
y=2
so, b=4
4/6*3/5 = 2/5
2/5*2/4 = 1/5
b/(b+y) * (b-1)/(b+y-1) = 2/5
b/(b+y) * (b-1)/(b+y-1) * (b-2)(b+y-2) = 1/5 = 1/2 * 2/5
so,
(b-2)/(b+y-2) = 1/2
2(b-2) = b+y-2
2b-4 = b+y-2
b = y+2
no idea about any red balls, but
(y+2)/(2y+2) * (y+1)/(2y+1) = 2/5
(y+2)/2(2y+1) = 2/5
5y+10 = 8y+4
3y = 6
y=2
so, b=4
4/6*3/5 = 2/5
2/5*2/4 = 1/5
b/(b+y) * (b-1)/(b+y-1) = 2/5
b/(b+y) * (b-1)/(b+y-1) * (b-2)(b+y-2) = 1/5 = 1/2 * 2/5
so,
(b-2)/(b+y-2) = 1/2
2(b-2) = b+y-2
2b-4 = b+y-2
b = y+2
no idea about any red balls, but
(y+2)/(2y+2) * (y+1)/(2y+1) = 2/5
(y+2)/2(2y+1) = 2/5
5y+10 = 8y+4
3y = 6
y=2
so, b=4
4/6*3/5 = 2/5
2/5*2/4 = 1/5
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