Consider the following hypothetical aqueous reaction: A (aq)-->B(aq)}. A flask is charged with 0.065 (mole) of A in a total volume of 100.0 (mL}. The following data are collected:

Time (min) 0 10 20 30 40
Moles of A .065 .051 .042 .035 .031

Calculate the average rate of disappearance of (A) between t = 0 min and t = 10 min, in units of M/S.

I have to do this for each time interval.

What's S? seconds?

moles A @ 0 min = 0.065
moles A @ 10 min = 0.051
delta A = 0.065-0.051 = 0.014 moles/10min = 0.0014 moles/min or (0.0014/0.100L)/min = 0.014M/min. Convert that to seconds if that is S.

Thanks so much :)

To calculate the average rate of disappearance of (A) between t = 0 min and t = 10 min, you can use the formula:

Average rate = (Change in concentration of A) / (Change in time)

In this case, the change in concentration of A is the difference between the initial concentration (0.065 mol) and the final concentration (0.051 mol), and the change in time is 10 minutes.

Average rate = (0.051 mol - 0.065 mol) / 10 min

After performing the calculation, the average rate of disappearance of A between t = 0 min and t = 10 min is -0.0014 M/min.

To calculate the average rate of disappearance of A between t = 0 min and t = 10 min, we need to find the change in the concentration of A over that time interval.

1. Find the initial concentration (C0) of A at t = 0 min. Given that the flask is charged with 0.065 moles of A in a total volume of 100.0 mL, we can convert it to Molarity (M):
Concentration (C0) = moles/volume
C0 = 0.065 moles / 0.100 L (since 100.0 mL = 0.100 L)
C0 = 0.65 M

2. Find the final concentration (Cf) of A at t = 10 min. From the data, we are given the moles of A at t = 10 min, which is 0.051 moles. So we need to convert it to Molarity using the total volume of the solution at t = 10 min (100.0 mL):
Concentration (Cf) = moles/volume
Cf = 0.051 moles / 0.100 L
Cf = 0.51 M

3. Calculate the change in concentration (ΔC) of A over the time interval:
ΔC = Cf - C0
ΔC = 0.51 M - 0.65 M
ΔC = -0.14 M

Note: The negative sign indicates a decrease in concentration.

4. Calculate the average rate of disappearance (r) of A using the change in concentration and the time interval:
r = ΔC / Δt
where Δt is the change in time (t = 10 min - t = 0 min)
Δt = 10 min - 0 min
Δt = 10 min

r = -0.14 M / 10 min
r = -0.014 M/min

Thus, the average rate of disappearance of A between t = 0 min and t = 10 min is approximately -0.014 M/min (or you can express it as M/s by converting minutes to seconds).