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October 21, 2014

October 21, 2014

Posted by **Destiny** on Thursday, February 9, 2012 at 2:35pm.

f(x)=0.2x^3-0.2x^2-5x-4

- College Alg -
**Steve**, Thursday, February 9, 2012 at 8:37pmf=1/5 (x+4)(x^2 - 5x - 5)

f' = .6x^2 - .4x - 5

f'=0 at x = 1/3 (1 ± 2√19)

f increases where f' > 0

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