Posted by jason on Thursday, February 9, 2012 at 11:45am.
Let the charge q1 be in left bottom corner, then clockwise q2 and q3, and q4 =10microC in the center.
The forces F14=F34.
The force
F24=1/(4πε0)(q2q4)/r2,
where r=a/sqroot2=58mm/ 1.41=38.9 mm=0.0389 m.
F24=(910^9)(410^-61010^-6)/(0.0389)^2=142.7N
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