Homework Help: physics

Posted by Hunter on Thursday, February 9, 2012 at 10:56am.

A small mailbag is released from a helicopter that is rising steadily at 2 m/sec. a) how long does it take the mailbag to stop moving? b) how high will the mailbag have risen in the time found in part a? c) how far did the helicopter move in the time found in part a?

physics - Elena, Thursday, February 9, 2012 at 12:34pm
The mailbag moves upwards with the initial velocity v0=2 m/s.
Its motion is decelerated
h = v0t - (gt^2)/2
v = v0 - gt.
If v=0, v0=gt and t = v0/g = 2/9.8=0.2 s.
h = 2•0.2-(9.8•0.04)/2 = 0.204 m
Helicopter moves uniformly, therefore,
H = vt = 2•0.2 = 0.4 m.

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