Posted by **angie** on Thursday, February 9, 2012 at 10:36am.

g(x)={1+cos(pi/2-x/1)

0

for-2 <or= x <or=2

for x<2 or x>2

is g(x) continuous at x=2 is it differentiable at x=2? ex[lain in detail I'm very confused as to how to solve this problem

- math/Calc -
**Steve**, Thursday, February 9, 2012 at 8:26pm
As written, it appears that

g(x) = 1+cos(pi/2 - x) = 1+sin(x)...

At x=2, that would make g(2) = 1+sin(2)

since g(2) is not 0, g is not continuous at x=2, since g(x)=0 for x>2.

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