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April 20, 2014

April 20, 2014

Posted by **Alex** on Thursday, February 9, 2012 at 9:48am.

- physics -
**Elena**, Thursday, February 9, 2012 at 5:16pmThe case of inelastic collision

m1•v1+m2•0=(m1+m2)•v

v= (m1•v1)/ (m1+m2).

It is necessary to know the mass of a piece of wood m2.

The change in kinetic energy is

ΔK=K1-K2 = m1(v1)^2/2 - (m1+m2)v^2/2.

For finding the percentage

((K1-K2)/K1) •100%

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