Wednesday

April 1, 2015

April 1, 2015

Posted by **Alex** on Thursday, February 9, 2012 at 9:48am.

- physics -
**Elena**, Thursday, February 9, 2012 at 5:16pmThe case of inelastic collision

m1•v1+m2•0=(m1+m2)•v

v= (m1•v1)/ (m1+m2).

It is necessary to know the mass of a piece of wood m2.

The change in kinetic energy is

ΔK=K1-K2 = m1(v1)^2/2 - (m1+m2)v^2/2.

For finding the percentage

((K1-K2)/K1) •100%

**Answer this Question**

**Related Questions**

AP physics - A 1.60-g bullet, moving at 542 m/s, strikes a 0.249-kg piece of ...

physics - A bullet of mass 0.0019 kg moving at 487 m/s embeds itself in a large ...

Physics - A bullet of mass kg moving at 500 m⁄s embeds itself in a large, ...

physics - A 0.0160-kg bullet traveling horizontally at 396 m/s strikes a 3.95-kg...

Physics help please - A 13.2 gm bullet is fired into a 12.0 kg wood block that ...

physics - A 25 g bullet is fired from a gun into a 1.35 kg block of wood ...

physics - A 20 g bullet moving horizontally with a speed v hits a 2-kg block of ...

Physics - A bullet with a mass of 0.01kg is fired horizontally into a block of ...

Physics - A .22 rifle bullet, traveling at 373m/s, strikes a block of soft wood...

physics - A bullet of mass 10 g has a speed of 500 m/s. a) What is its kinetic ...