Homework Help: physics

Posted by hannah on Thursday, February 9, 2012 at 9:06am.

The density of ice is 917 kg/m3, and the density of sea water is 1025 kg/m3. A swimming polar bear climbs onto a piece of floating ice that has a volume of 4.41 m3. What is the weight of the heaviest bear that the ice can support without sinking completely beneath the water? please help!

physics - Henry, Saturday, February 11, 2012 at 6:47am
Vb = (Do/Df)*Vo,
Vb = (917/1025) * 4.41 = 3.95 m^3.

(917+Db)/1025 = 1,max.
917 + Db = 1025,
Db = 1025 - 917 = 108 kg/m^3 = Density of bear.

Wb = 108kg/m^3 * 4.41m^3 * 9.8N/kg =
4668 N.
physics - Henry, Saturday, February 11, 2012 at 6:52am
NOTE:
Do = Density of object(ice).
Df = Density of fluid.
Db = Density of bear.

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