Posted by **Kristi** on Wednesday, February 8, 2012 at 11:08pm.

Write an equation of the line containing the given point and perpendicular to the given line. Express your answer in the form y=mx+b. (2,4) 3x+y=6 The equation of line is y=, and explain how you have gotten the answer.

- Algebra -
**Elle**, Thursday, February 9, 2012 at 4:26am
1. First you need to find the slope of the original line you are given which is 3x + y = 6. The slope is -A/B so it is -3/1 or just -3, m = -3.

2. The slope of a line perpendicular is the negative reciprocal so the slope of the line perpendicular to the given line is 1/3.

3. Use point slope form with the given point to find the equation of the line first before simplifying it to y=mx+b.

Point slope form is y - y1 = m(x-x1) now substitute the point

y-4=1/3(x-2)

4. Now distribute the 1/3: y-4=1/3x - 2/3

Then add 4 to the other side, make 4 into 12/3 to give it a command denominator making it easier to add.

y = 1/3x + 10/3.

- Algebra -
**Kristi**, Thursday, February 9, 2012 at 7:22am
Thank You so much Elle

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