The specific heat of a certain type of metal is 0.128 J/(g-c). What is the final temperature if 305 J of heat is added to 86.9 g of this metal initially at 20 degrees C? Tfinal = ___ C
q = 305J = mass metal x specific heat x (Tfinal-Tinitial). Substitute and solve for Tfinal.
ohhhhhhhh so 305J = (86.9)(0.128)(Tf-20)
305J = (11.1232)(Tf-20C)
305J = 11.1232[Tf] - 222.464
527.464 = 11.1232[Tf]
Tf = 47.42 C
is that correct..?
To find the final temperature, we can use the formula:
Q = m * C * ΔT
Where:
Q = heat added (in Joules)
m = mass of the metal (in grams)
C = specific heat of the metal (in J/(g-C))
ΔT = change in temperature (Tfinal - Tinitial)
We are given:
Q = 305 J
m = 86.9 g
C = 0.128 J/(g-C)
Tinitial = 20°C
Let's rearrange the formula to solve for ΔT:
ΔT = Q / (m * C)
Substituting the given values:
ΔT = 305 J / (86.9 g * 0.128 J/(g-C))
Now, let's calculate ΔT:
ΔT = 305 J / (11.1392 g-C/J)
ΔT ≈ 27.41 °C
To find Tfinal, we can add ΔT to the initial temperature:
Tfinal = Tinitial + ΔT
Tfinal = 20 °C + 27.41 °C
Calculating Tfinal:
Tfinal ≈ 47.41 °C
Therefore, the final temperature is approximately 47.41 °C.
To find the final temperature, we can use the formula:
q = m * c * ΔT
Where:
q is the heat energy absorbed or released by the object,
m is the mass of the object,
c is the specific heat of the object,
and ΔT is the change in temperature.
In this case, we know the heat energy (q) is 305 J, the mass (m) is 86.9 g, the specific heat (c) is 0.128 J/(g°C), and the initial temperature (Tinitial) is 20°C.
Rearranging the formula to solve for ΔT:
ΔT = q / (m * c)
Substituting the given values:
ΔT = 305 J / (86.9 g * 0.128 J/(g°C))
ΔT = 305 J / (11.1452 g°C/J)
ΔT ≈ 27.37°C
To find the final temperature (Tfinal), we add the change in temperature (ΔT) to the initial temperature (Tinitial):
Tfinal = Tinitial + ΔT
Tfinal = 20°C + 27.37°C
Tfinal ≈ 47.37°C
Therefore, the final temperature is approximately 47.37°C.