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August 30, 2014

August 30, 2014

Posted by **Jake** on Wednesday, February 8, 2012 at 8:42pm.

a) slope -2/3, passing through (0,6)

b) passing through points (2,7) and (6,11)

c) parallel to y=4x-6 passing through point (2,6)

- Calculus -
**chemath**, Wednesday, February 8, 2012 at 8:54pma) We use the slope-point formula

y-y1 = m (x - x1)

y - 6 = -2/3(x - 0)

y - 6 = -2/3x + 0

y = -2/3x + 6

b) first we found the slope using the two points

m = y2 - y1 / x2 - x1

m = 11 - 7 / 7 - 2

m = 4 / 5

then use the point-slope formula as in (a) to find the equation

c) We know that in order for two lines two be

parallel they must to have the same slope.

So, the slope in the given equation is m = 4

Now, by taken m = 4 and the point (2, 6) and using

again the point-slope formula as in example (a) we find the equation.

- Calculus -
**bobpursley**, Wednesday, February 8, 2012 at 8:56pmGood teaching, Chemath.

- Calculus -
**Jake**, Wednesday, February 8, 2012 at 9:27pmThank you~~

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