posted by Jake on .
Determine the equation of the line described by the given information.
a) slope -2/3, passing through (0,6)
b) passing through points (2,7) and (6,11)
c) parallel to y=4x-6 passing through point (2,6)
a) We use the slope-point formula
y-y1 = m (x - x1)
y - 6 = -2/3(x - 0)
y - 6 = -2/3x + 0
y = -2/3x + 6
b) first we found the slope using the two points
m = y2 - y1 / x2 - x1
m = 11 - 7 / 7 - 2
m = 4 / 5
then use the point-slope formula as in (a) to find the equation
c) We know that in order for two lines two be
parallel they must to have the same slope.
So, the slope in the given equation is m = 4
Now, by taken m = 4 and the point (2, 6) and using
again the point-slope formula as in example (a) we find the equation.
Good teaching, Chemath.