calculus
posted by cassie .
I'm having trouble with these two problems. If someone can help me with the first one I can probably get the second one on my own. I think that I have to factor the bottom but I just cant get it.
lim (3x+7)/(8x^23x+11)
x> infinity

multipy numerator and denomiantor by 1/x^2
lim (3/x+7/x^2)/(83/x+11/x^2)
lim numerator is zero
lim denominator is 8
lim then must be zero.